$2 \times 10^{8}$ atoms of carbon are arranged side by side.
Question.

$2 \times 10^{8}$ atoms of carbon are arranged side by side. Calculate the radius of carbon atom if the length of this arrangement is $2.4 \mathrm{~cm}$.

Solution:

Length of the given arrangement = 2.4 cm

Number of carbon atoms present $=2 \times 10^{8}$

Diameter of carbon atom

$=\frac{2.4 \times 10^{-2} \mathrm{~m}}{2 \times 10^{8}}$

$=1.2 \times 10^{-10} \mathrm{~m}$

$\therefore$ Radius of carbon atom $=\frac{\text { Diameter }}{2}$

$=\frac{1.2 \times 10^{-10} \mathrm{~m}}{2}$

$=6.0 \times 10^{-11} \mathrm{~m}$
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