8 taps of the same size fill a tank in 27 minutes.

Question:

8 taps of the same size fill a tank in 27 minutes. If two taps go out of order, how long would the remaining taps take to fill the tank?

Solution:

Let x min be the required number of time. Then, we have:

No. of taps 8 6
Time (in min) 27 x">xx

Clearly, less number of taps will take more time to fill the tank .

So, it is a case of inverse proportion.

Now, $8 \times 27=6 \times x$

$\Rightarrow x=\frac{8 \times 27}{6}$

$\Rightarrow x=36$

Therefore, it will take 36 min to fill the tank.

 

Leave a comment

Comments

Sept. 14, 2023, 5:43 p.m.
Cole Chanter
March 11, 2023, 7:29 p.m.
Hello esaral.com administrator, Keep sharing your knowledge!
Abhay
Dec. 7, 2022, 7:01 p.m.
But in my book the answer is 108 min
Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now