A 10 m long horizontal wire extends from North East to South West.
Question:

A $10 \mathrm{~m}$ long horizontal wire extends from North East to South West. It is falling with a speed of $5.0 \mathrm{~ms}^{-1}$, at right angles to the horizontal component of the earth’s magnetic field, of $0.3 \times 10^{-4} \mathrm{~Wb} / \mathrm{m}^{2}$. The value of the induced emf in wire is :

  1. (1) $1.5 \times 10^{-3} \mathrm{~V}$

  2. (2) $1.1 \times 10^{-3} \mathrm{~V}$

  3. (3) $2.5 \times 10^{-3} \mathrm{~V}$

  4. (4) $0.3 \times 10^{-3} \mathrm{~V}$


Correct Option: 1

Solution:

(1) Induced emf, $\varepsilon=\mathrm{B} v \ell$

$=0.3 \times 10^{-4} \times 5 \times 10$

$=1.5 \times 10^{-3} \mathrm{~V}$

Administrator

Leave a comment

Please enter comment.
Please enter your name.