Question:
A bag contains 5 red, 8 black and 7 white balls. One ball is chosen at random. What is the probability that the chosen ball is black?
(a) $\frac{2}{3}$
(b) $\frac{2}{5}$
(c) $\frac{3}{5}$
(d) $\frac{1}{3}$
Solution:
(b) $\frac{2}{5}$
Explanation:
Total number of balls in the bag = 5 + 8 + 7 = 20
Number of black balls = 8
Let E be the event that the chosen ball is black.
$\therefore$ Required probability $=P(E)=\frac{8}{20}=\frac{2}{5}$
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