Question:
A bag contains 8 red, 2 black and 5 white balls. One ball is drawn at random. What is the probability that the ball drawn is not black?
(a) $\frac{18}{15}$
(b) $\frac{2}{15}$
(c) $\frac{13}{15}$
(d) $\frac{1}{3}$
Solution:
(c) $\frac{13}{15}$
Explanation:
Total possible outcomes = Total number of balls
= ( 8 + 2 + 5) = 15
Total number of non-black balls = (8 + 5) = 13
$\therefore P$ (getting a ball that is not black) $=\frac{13}{15}$
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