A box contains 3 blue, 2 white and 4 red marbles. If a marbles.
Question:

A box contains 3 blue, 2 white and 4 red marbles. If a marbles. If a marble is drawn at random from the box, what is the probability that it will not be a white marble?

(a) $\frac{1}{3}$

(b) $\frac{4}{9}$

(C) $\frac{7}{9}$

(d) $\frac{2}{9}$

Solution:

(C) $\frac{7}{9}$

Explanation:
Total possible outcomes = Total number of marbles

= ( 3 + 2 + 4) = 9

Let E be the event of not getting a white marble.
It means the marble can be either blue or red but not white.
Number of favourable outcomes =  (3 + 4) = 7 marbles

$\therefore P($ not getting a white marble $)=\frac{7}{9}$