Question:
A certain gas obeys $P\left(V_{m}-b\right)=R T$. The value of $\left(\frac{\partial Z}{\partial P}\right)_{T}$ is $\frac{x b}{R T}$. The value of $x$ is
Solution:
(1)
$P(v-b)=R T$
$P V-P b=R T$
$\frac{P V}{R T}-\frac{P b}{R T}=1$
$Z=1+\frac{P V}{R T}$
$\frac{d z}{d p}=0+\frac{b}{R T}$
$\Rightarrow \frac{b}{R T}=\frac{x b}{R T}$
$x=1$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.