Question:
A common transistor radio set requires $12 \mathrm{~V}$ (D.C.) for its operation. The D.C. source is constructed by using a transformer and a rectifier circuit, which are operated at $220 \mathrm{~V}$ (A.C.) on standard domestic A.C. supply. The number of turns of secondary coil are 24 , then the number of turns of primary are
Solution:
$\frac{N_{P}}{N_{S}}=\frac{V_{P}}{V_{S}}$
$\frac{N_{P}}{24}=\frac{220}{12}$
$N_{P}=\frac{220 \times 24}{12}$
$N_{P}=440$
Ans. 440 turns
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.