A conical tent is 10 m high and the radius of its base is 24 m. Find

Solution:



(i) Let ABC be a conical tent.

Height (h) of conical tent = 10 m

Radius (r) of conical tent = 24 m

Let the slant height of the tent be l.

In $\triangle \mathrm{ABO}$

$\mathrm{AB}^{2}=\mathrm{AO}^{2}+\mathrm{BO}^{2}$

$p^{2}=h^{2}+r^{2}$

$=(10 \mathrm{~m})^{2}+(24 \mathrm{~m})^{2}$

$=676 \mathrm{~m}^{2}$

$\therefore I=26 \mathrm{~m}$

Therefore, the slant height of the tent is 26 m.

(ii) CSA of tent $=\pi r l$

$=\left(\frac{22}{7} \times 24 \times 26\right) \mathrm{m}^{2}$

$=\frac{13728}{7} \mathrm{~m}^{2}$

Cost of $1 \mathrm{~m}^{2}$ canvas $=$ Rs 70

Cost of $\frac{13728}{7} \mathrm{~m}^{2}$ canvas $=\operatorname{Rs}\left(\frac{13728}{7} \times 70\right)$

$=\mathrm{Rs} 137280$

Therefore, the cost of the canvas required to make such a tent is

Rs 137280 .