Question.
A cuboidal vessel is 10 m long and 8 m wide. How high must it be made to hold 380 cubic metres of a liquid?
Solution:
Let the height of the cuboidal vessel be h.
Length (l) of vessel = 10 m
Width (b) of vessel = 8 m
Volume of vessel $=380 \mathrm{~m}^{3}$
$\therefore / \times b \times h=380$
$[(10)(8) h] \mathrm{m}^{2}=380 \mathrm{~m}^{3}$
$h=4.75 \mathrm{~m}$
Therefore, the height of the vessel should be 4.75 m.
Let the height of the cuboidal vessel be h.
Length (l) of vessel = 10 m
Width (b) of vessel = 8 m
Volume of vessel $=380 \mathrm{~m}^{3}$
$\therefore / \times b \times h=380$
$[(10)(8) h] \mathrm{m}^{2}=380 \mathrm{~m}^{3}$
$h=4.75 \mathrm{~m}$
Therefore, the height of the vessel should be 4.75 m.
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