A die is tossed thrice. Find the probability of getting an odd number at least once.

Probability of getting an odd number in a single throw of a die $=\frac{3}{6}=\frac{1}{2}$

Similarly, probability of getting an even number $=\frac{3}{6}=\frac{1}{2}$

Probability of getting an even number three times $=\frac{1}{2} \times \frac{1}{2} \times \frac{1}{2}=\frac{1}{8}$

Therefore, probability of getting an odd number at least once

$=1$ - Probability of getting an odd number in none of the throws

$=1$ - Probability of getting an even number thrice

$=1-\frac{1}{8}$

$=\frac{7}{8}$