A group consists of 12 persons, of which 3 are extremely patient, other 6 are extremely honest and rest are extremely kind. A person form the group is selected at random. Assuming that each person is equally likely to be selected, find the probability of selecting a person who is
(i) extremely patient
(ii) extremely kind or honest. Which of the above you prefer more. [CBSE 2013]
Number of persons in the group = 12
∴ Total number of outcomes = 12
(i) Number of persons who are extremely patient = 3
So, the favourable number of outcomes are 3.
$\therefore \mathrm{P}$ (selecting a person who is extremely patient) $=\frac{\text { Favourable number of outcomes }}{\text { Total number of outcomes }}=\frac{3}{12}=\frac{1}{4}$
(ii) Number of persons who are extremely honest = 6
Number of persons who are extremely kind = 12 − (3 + 6) = 3
∴ Number of persons who are extremely kind or honest = 6 + 3 = 9
So, the favourable number of outcomes are 9.
$\therefore \mathrm{P}($ selecting a person who is extremely kind or honest $)=\frac{\text { Favourable number of outcomes }}{\text { Total number of outcomes }}=\frac{9}{12}=\frac{3}{4}$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.