A jet plane is travelling towards west at a speed of 1800 km/h.

Question:

A jet plane is travelling towards west at a speed of 1800 km/h. What is the voltage difference developed between the ends of the wing having a span of 25 m, if the Earth’s magnetic field at the location has a magnitude of 5 × 10−4 T and the dip angle is 30°.

Solution:

Speed of the jet plane, v = 1800 km/h = 500 m/s

Wing spanof jet plane, l = 25 m

Earth’s magnetic field strength, B = 5.0 × 10−4 T

Angle of dip, $\delta=30^{\circ}$

Vertical component of Earth’s magnetic field,

$B_{V}=B \sin \delta$

$=5 \times 10^{-4} \sin 30^{\circ}$

$=2.5 \times 10^{-4} \mathrm{~T}$

Voltage difference between the ends of the wing can be calculated as:

e = (BV) × l × v

= 2.5 × 10−4 × 25 × 500

= 3.125 V

Hence, the voltage difference developed between the ends of the wings is

3.125 V.

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