A man saved Rs 16500 in ten years.

Let the amount saved by the man in the first year be Rs A.

Let d be the common difference.

Let $S_{10}$ denote the amount he saves in ten years.

Here, n =10, d =100

We know:

$S_{n}=\frac{n}{2}\{2 A+(n-1) d\}$

$\therefore S_{10}=\frac{10}{2}\{2 A+(10-1) 100\}$

$\Rightarrow 16500=5\{2 A+900\}$

$\Rightarrow 3300=2 A+900$

$\Rightarrow A=1200$

Therefore, the man saved Rs 1200 in the first year.