A point charge

Question:

A point charge of $+12 \mu \mathrm{C}$ is at a distance $6 \mathrm{~cm}$ vertically above the centre of a square of side $12 \mathrm{~cm}$ as shown in figure. The magnitude of the electric flux through the square will beĀ  ____________$\times 10^{3} \mathrm{Nm}^{2} / \mathrm{C}$.

Solution:

From symmetry $\phi=\frac{1}{6}\left(\frac{\mathrm{q}}{\varepsilon_{0}}\right)$

$=\frac{12 \times 10^{-6}}{6 \times 8.85 \times 10^{-12}}$

$=225.98 \times 10^{3} \frac{\mathrm{Nm}^{2}}{\mathrm{~s}}$

$\simeq 226 \times 10^{3} \frac{\mathrm{Nm}^{2}}{\mathrm{C}}$

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