A railway half ticket costs half the full fare and the reservation charge is the same on half ticket as on full ticket.

Solution:

Let take first class full of fare is Rs $x$ and reservation charge is Rs $y$ per ticket

Then half of the ticket as on full ticket $=\frac{x}{2}$

According to the given condition we have

$x+y=216 \cdots(i)$

$x+y+\left(\frac{x}{2}\right)+y=327$

$x+\frac{x}{2}+y+y=327$

$\frac{3 x}{2}+2 y=327 \cdots(i i)$

Multiplying equation  by 2 we have

$2 x+2 y=432 \cdots(\mathrm{iii})$

Subtracting $(i i)$ from $(i i i)$ we get

$\frac{4 x-3 x}{2}=105$

$\frac{1 x}{2}=105$

$x=105 \times 2$

$x=210$

Putting $x=210$ in equation $(i)$ we get

$x+y=216$

$210+y=216$

$y=216-210$

$y=6$

Hence, the basic first class full fare is 210

The reservation charge is Rs 6 .