A rational number lying between
Question:

A rational number lying between $\sqrt{2}$ and $\sqrt{3}$ is

(a) $\frac{(\sqrt{2}+\sqrt{3})}{2}$

(b) $\sqrt{6}$

(c) $1.6$

(d) $1.9$

Solution:

Since, $\frac{(\sqrt{2}+\sqrt{3})}{2}$ and $\sqrt{6}$ are irrational numbers,

And, $\sqrt{2}=1.414$ and $\sqrt{3}=1.732$

So, the rational number lying between $\sqrt{2}$ and $\sqrt{3}$ is $1.6$.

Hence, the correct option is (c).