Question:
A rational number lying between $\sqrt{2}$ and $\sqrt{3}$ is
(a) $\frac{(\sqrt{2}+\sqrt{3})}{2}$
(b) $\sqrt{6}$
(c) $1.6$
(d) $1.9$
Solution:
Since, $\frac{(\sqrt{2}+\sqrt{3})}{2}$ and $\sqrt{6}$ are irrational numbers,
And, $\sqrt{2}=1.414$ and $\sqrt{3}=1.732$
So, the rational number lying between $\sqrt{2}$ and $\sqrt{3}$ is $1.6$.
Hence, the correct option is (c).
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