A rectangular sheet of paper, 44 cm × 20 cm,
Question:

A rectangular sheet of paper, 44 cm × 20 cm, is rolled along its length to form a cylinder. Find the total surface area of the cylinder thus generated.

Solution:

The rectangular sheet of paper $44 \mathrm{~cm} \times 20 \mathrm{~cm}$ is rolled along its length to form a cylinder. The height of the cylinder is $20 \mathrm{~cm}$ and circumference is $44 \mathrm{~cm}$.

We have:

Height, $h=20 \mathrm{~cm}$

Circumference $=2 \pi r=44 \mathrm{~cm}$

$\therefore$ Total surface area is $S=2 \pi r h$

$=44 \times 20 \mathrm{~cm}^{2}$

The rectangular sheet of paper $44 \mathrm{~cm} \times 20 \mathrm{~cm}$ is rolled along its length to form a cylinder. The height of the cylinder is $20 \mathrm{~cm}$ and circumference is $44 \mathrm{~cm}$.

We have:

Height, $h=20 \mathrm{~cm}$

Circumference $=2 \pi r=44 \mathrm{~cm}$

$\therefore$ Total surface area is $S=2 \pi r h$

$=44 \times 20 \mathrm{~cm}^{2}$

$=880 \mathrm{~cm}^{2}$

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