A society collected Rs 92.16. Each member collected as many paise as there were members.
Question:

A society collected Rs 92.16. Each member collected as many paise as there were members. How many members were there and how much did each contribute?

Solution:

Let be the number of members.

Let be the amount in paise donated by each member.

The total contribution can be expressed as follows:

M x r = Rs 92.16 = 9216 paise

Since the amount received as donation is the same as the number of members:

$\therefore r=M$

Substituting this in the first equation, we get:

M x M = 9216

M2 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3

M2 = (2 x 2) x (2 x 2) x (2 x 2) x (2 x 2) x (2 x 2) x (3 x 3)

M = 2 x 2 x 2 x 2 x 2 x 3 = 96

To find r, we can use the relation r = M.

Let be the number of members.

Let be the amount in paise donated by each member.

The total contribution can be expressed as follows:

M x r = Rs 92.16 = 9216 paise

Since the amount received as donation is the same as the number of members:

$\therefore r=96$

So, there are 96 members and each paid 96 paise.