**Question:**

A soft drink is available in two packs-

(i) a tin can with a rectangular base of length 5 cm and width 4 cm, having a height of 15 cm and

(ii) a plastic cylinder with circular base of diameter 7 cm and height 10 cm, Which container has greater capacity and by how much?

**Solution:**

Given,

The tin can will be cubical in shape.

Length (L) of tin can = 5 cm

Breadth (B) of tin can = 4 cm

Height (H) of tin can = 15 cm

Capacity of the tin can $=1 \times \mathrm{b} \times \mathrm{h}=(5 \times 4 \times 15) \mathrm{cm}^{3}$

Radius (R) of the circular end of the plastic cylinder = 7/2 cm = 3.5 cm

Height (H) of plastic cylinder = 10 cm

Capacity of plastic cylinder $=\pi R^{2} H=22 / 7 \times(3.5)^{2} \times 10 \mathrm{~cm}^{3}=385 \mathrm{~cm}^{3}$

Therefore, the plastic cylinder has greater capacity.

Difference in capacity $=(385-300) \mathrm{cm}^{3}=85 \mathrm{~cm}^{3}$