A wooden article was made by scooping out a hemisphere from each end of a solid cylinder, as shown in fig.

Radius of the cylinder (r) = 3.5 cm

Height of the cylinder (h) = 10 cm

$\therefore$ Curved surface area of cylinder $=2 \pi \mathrm{rh}$

$=2 \times \frac{22}{7} \times \frac{35}{10} \times 10 \mathrm{~cm}^{2}=220 \mathrm{~cm}^{2}$

Curved surface area of a hemisphere $=2 \pi \mathrm{r}^{2}$

$\therefore$ Curved surface area of both hemispheres

$=2 \times 2 \pi r^{2}=4 \pi r^{2}=4 \times \frac{\mathbf{2 2}}{\mathbf{7}} \times \frac{\mathbf{3 5}}{\mathbf{1 0}} \times \frac{\mathbf{3 5}}{\mathbf{1 0}} \mathrm{cm}^{2}=154 \mathrm{~cm}^{2}$

Total surface area of the remaining solid

$=(220+154) \mathrm{cm}^{2}=374 \mathrm{~cm}^{2}$