ABC is a right angled triangle in which ∠A = 90° and AB = AC. Find ∠B and ∠C.
Given that ABC is a right angled triangle such that ∠A = 90° and AB = AC
Since, AB = AC
ΔABC is also isosceles.
Therefore, we can say that ΔABC is right angled isosceles triangle.
∠C = ∠B and ∠A = 90° … (i)
Now, we have sum of angled in a triangle = 180°
∠A + ∠B + ∠C = 180°
90° + ∠B + ∠B = 180° [From (i)]
2∠B = 180° – 90°
∠B = 45°
Therefore, ∠B = ∠C = 45°