ABC is a right angled triangle in which ∠A = 90° and AB = AC. Find ∠B and ∠C.

Given that ABC is a right angled triangle such that ∠A = 90° and AB = AC

Since, AB = AC

ΔABC is also isosceles.

Therefore, we can say that ΔABC is right angled isosceles triangle.

∠C = ∠B and ∠A = 90° ... (i)

Now, we have sum of angled in a triangle = 180°

∠A + ∠B + ∠C = 180°

90° + ∠B + ∠B = 180° [From (i)]

2∠B = 180° - 90°

∠B = 45°

Therefore, ∠B = ∠C = 45°