An army contingent of 616 members is to march behind an army band of 32 members in a parade
Question.

An army contingent of 616 members is to march behind an army band of 32 members in a parade. The two groups are to march in the same number of columns. What is the maximum number of columns in which they can march?

Solution:

616 and 32

$616=32 \times 19+8$

$32=4 \times 8$

$\operatorname{HCF}$ of $(616,32)=8$
Editor

Leave a comment

Please enter comment.
Please enter your name.