Question.
An artificial satellite is moving in a circular orbit of radius 42250 km. Calculate its speed if it takes 24 hours to revolve around the earth.
An artificial satellite is moving in a circular orbit of radius 42250 km. Calculate its speed if it takes 24 hours to revolve around the earth.
Solution:
Distance covered by the satellite in 24 hours.
$S=2 \pi r$
$=2 \times \frac{22}{7} \times 42250$
$=265571.43 \mathrm{~km}$
Therefore speed of satellite
$v=\frac{\text { distance travelled }}{\text { time taken }}=\frac{265571.43}{24 \times 60 \times 60}=3.07 \mathrm{kms}^{-1}$
Distance covered by the satellite in 24 hours.
$S=2 \pi r$
$=2 \times \frac{22}{7} \times 42250$
$=265571.43 \mathrm{~km}$
Therefore speed of satellite
$v=\frac{\text { distance travelled }}{\text { time taken }}=\frac{265571.43}{24 \times 60 \times 60}=3.07 \mathrm{kms}^{-1}$
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