An unsaturated hydrocarbon X on ozonolysis gives A.

An unsaturated hydrocarbon $\mathrm{X}$ on ozonolysis gives $\mathrm{A}$. Compound $\mathrm{A}$ when warmed with ammonical silver nitrate forms a bright silver mirror along the sides of the test tube. The unsaturated hydrocarbon $X$ is:

Correct Option: , 3


As (A) compound given positive tollen’s test hence it may consist – $\mathrm{CHO}$ (aldehyde group). or it can be $\mathrm{HCOOH}$ So for the given option:


and for other compounds (options):

(d) $\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{3} \stackrel{\text { Ozonolysis }}{\longrightarrow} 2 \mathrm{CH}_{3}-\mathrm{COOH}$

(Does not show tollen’s test)


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