An unsaturated hydrocarbon $\mathrm{X}$ on ozonolysis gives $\mathrm{A}$. Compound $\mathrm{A}$ when warmed with ammonical silver nitrate forms a bright silver mirror along the sides of the test tube. The unsaturated hydrocarbon $X$ is:
Correct Option: , 3
As (A) compound given positive tollen's test hence it may consist - $\mathrm{CHO}$ (aldehyde group). or it can be $\mathrm{HCOOH}$ So for the given option:
(c)
and for other compounds (options):
(d) $\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{3} \stackrel{\text { Ozonolysis }}{\longrightarrow} 2 \mathrm{CH}_{3}-\mathrm{COOH}$
(Does not show tollen's test)
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