Arrange the following metal complex/ compounds in the increasing order of spin only magnetic moment.

(a) $\mathrm{Ce} \rightarrow[\mathrm{Xe}] 4 \mathrm{f}^{2} 5 \mathrm{~d}^{0} 6 \mathrm{~s}^{2}$

In complex $\mathrm{Ce}^{4+} \rightarrow[\mathrm{Xe}] 4 \mathrm{f}^{0} 5 \mathrm{~d}^{0} 6 \mathrm{~s}^{0}$

there is no unpaired electron so $\mu_{\mathrm{m}}=0$

(b) ${ }_{64} \mathrm{Gd}^{3+} \rightarrow[\mathrm{Xe}] 4 \mathrm{f}^{7} 5 \mathrm{~d}^{0} 6 \mathrm{~s}^{0}$

contain seven unpaired electrons so, $\mu_{\mathrm{m}}=\sqrt{7(7+2)}=\sqrt{63}$ B.M.

(c) ${ }_{63} \mathrm{Eu}^{3+} \rightarrow\left[{ }_{54} \mathrm{Xe}\right] 4 \mathrm{f}^{6} 5 \mathrm{~d}^{0} 6 \mathrm{~s}^{0}$

contain six unpaired electron

so, $\mu_{\mathrm{m}}=\sqrt{6(6+2)}=\sqrt{48}$ B. M

Hence, order of spin only magnetic movement

$\mathrm{b}>\mathrm{c}>\mathrm{a}$