Question:
As shown in the figure, a particle of mass $10 \mathrm{~kg}$ is placed at a point $\mathrm{A}$.
When the particle is slightly displaced to its right, it starts moving and reaches the point $\mathrm{B}$. The speed of the particle at $\mathrm{B}$ is $\mathrm{xm} / \mathrm{s}$. (Take $\left.\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)$
The value of 'x' to the nearest integer is_____
Solution:
(10)
Using work energy theorem,
$\mathrm{W}_{\mathrm{g}}=\Delta \mathrm{K} . \mathrm{E}$
$(10)(g)(5)=\frac{1}{2}(10) v^{2}-0$
$\mathrm{v}=10 \mathrm{~m} / \mathrm{s}$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.