By taking three different values of n verify the truth of the following statements:

Solution:

(i)
Let the three even natural numbers be 2, 4 and 8.

Cubes of these numbers are: 

$2^{3}=8,4^{3}=64,8^{3}=512$

By divisibility test, it is evident that 8,64 and 512 are divisible by 2 .

Thus, they are even.

This verifies the statement.

(ii)
Let the three odd natural numbers be 3, 9 and 27.

Cubes of these numbers are: 

$3^{3}=27,9^{3}=729,27^{3}=19683$

By divisibility test, it is evident that 27,729 and 19683 are divisible by $3 .$

Thus, they are odd.

This verifies the statement.

(iii)
Three natural numbers of the form $(3 n+1)$ can be written by choosing $n=1,2,3 \ldots$ etc.

Let three such numbers be 4,7 and 10 .

Cubes of the three chosen numbers are: 

$4^{3}=64,7^{3}=343$ and $10^{3}=1000$

Cubes of 4,7 and 10 can expressed as:

$64=3 \times 21+1$, which is of the form $(3 n+1)$ for $n=21$

$343=3 \times 114+1$, which is of the form $(3 n+1)$ for $n=114$

$1000=3 \times 333+1$, which is of the form $(3 n+1)$ for $n=333$

Cubes of 4,7, and 10 can be expressed as the natural numbers of the form $(3 n+1)$ for some natural number $n$. Hence, the statement is verified.

(iv)
Three natural numbers of the form $(3 p+2)$ can be written by choosing $p=1,2,3 \ldots$ etc.

Let three such numbers be 5,8 and 11 .

Cubes of the three chosen numbers are:

$5^{3}=125,8^{3}=512$ and $11^{3}=1331$

Cubes of 5,8, and 11 can be expressed as:

$125=3 \times 41+2$, which is of the form $(3 p+2)$ for $p=41$

$512=3 \times 170+2$, which is of the form $(3 p+2)$ for $p=170$

$1331=3 \times 443+2$, which is of the form $(3 p+2)$ for $p=443$

Cubes of 5,8, and 11 could be expressed as the natural numbers of the form $(3 p+2)$ for some natural number $p$. Hence, the statement is verified.