Calculate the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar.

Question:

Calculate the temperature of 4.0 mol of a gas occupying 5 dmat 3.32 bar.

$\left(\mathrm{R}=0.083\right.$ bar $\left.\mathrm{dm}^{3} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right)$

 

Solution:

Given,

n = 4.0 mol

V = 5 dm3

p = 3.32 bar

R = 0.083 bar dm3 K–1 mol–1

The temperature (T) can be calculated using the ideal gas equation as:

$p V=n \mathrm{R} T$

$\Rightarrow T=\frac{p V}{n \mathrm{R}}$

$=\frac{3.32 \times 5}{4 \times 0.083}$

$=50 \mathrm{~K}$

Hence, the required temperature is 50 K.

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