Complete combustion of $750 \mathrm{~g}$ of an organic compound provides $420 \mathrm{~g}$ of $\mathrm{CO}_{2}$ and $210 \mathrm{~g}$ of $\mathrm{H}_{2} \mathrm{O}$. The percentage composition of carbon and hydrogen in organic compound is $15.3$ and....respectively. (Round off to the Nearest Integer)
(3)
$44 \mathrm{gm} \mathrm{CO}_{2}$, have $12 \mathrm{gm}$ carbon
So, $420 \mathrm{gmCO}_{2} \Rightarrow \frac{12}{44} \times 420$
$\Rightarrow \frac{1260}{11}$ gm carbon
$\Rightarrow 114.545$ gram carbon
So, $\%$ of carbon $=\frac{\frac{114.545}{750} \times 100}{4}$
$\simeq 15.3 \%$
$18 \mathrm{gmH}_{2} \mathrm{O} \Rightarrow 2 \mathrm{gmH}_{2}$
$210 \mathrm{gm} \Rightarrow \frac{2}{18} \times 210$
$=23.33 \mathrm{gmH}_{2}$
So, $\% \mathrm{H}_{2} \Rightarrow \frac{23.33}{750} \times 100=3.11 \%$
$\approx 3 \%$
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