Complex X of composition
Question:

Complex X of composition $\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6} \mathrm{Cl}_{\mathrm{n}}$ has a spin only magnetic moment of $3.83 \mathrm{BM}$. It reacts with $\mathrm{AgNO}_{3}$ and shows geometrical isomerism. The IUPAC nomenclature of $X$ is:

  1.  Hexaaqua chromium (III) chloride

  2. Tetraaquadichlorido chromium (IV) chloride dihydrate

  3.  Dichloridotetraaqua chromium (IV) chloride dihydrate

  4. Tetraaquadichlorido chromium (III) chloride dihydrate


Correct Option: , 4

Solution:

$\mu=\sqrt{n(n+2)}$ B.M. $=3.83$ B.M.

$n=3\left(n=\right.$ No. of unpaired $\left.e^{-}\right)$

Therefore, oxidation number of $\mathrm{Cr}$ should be $+3$.

Hence complex is $\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6} \mathrm{Cl}_{3}$.

Complex shows geometrical isomerism therefore formula of complex is $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4} \mathrm{Cl}_{2}\right] \mathrm{Cl} .2 \mathrm{H}_{2} \mathrm{O}$.

IUPAC Name:

Tetraaquadichlorido chromium(III)

Chloridedihydrate

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