Construct a parallelogram ABCD in which AB = 4.3 cm,
Question:

Construct a parallelogram ABCD in which AB = 4.3 cm, AD = 4 cm and BD = 6.8 cm.

Solution:

Steps of construction:

Step 1: Draw $A B=4.3 \mathrm{~cm}$

Step 2: With $B$ as the centre, draw an arc of $6.8 \mathrm{~cm}$.

Step 3: With $A$ as the centre, draw another $\operatorname{arc}$ of $4 \mathrm{~cm}$, cutting the previous arc at $D$.

Step 4: Join $B D$ and $A D$.

Step 5: We know that the opposite sides of a parallelogram are equal.

Thus, with $D$ as the centre, draw an arc of $4.3 \mathrm{~cm}$.

Step 6: With $B$ as the centre, draw another $\operatorname{arc} 4 \mathrm{~cm}$, cutting the previous arc at $C$.

Step 7: Join $C D$ and $B C$.

​then, ABCD is the required parallelogram.