Question:
Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm.
Solution:
Steps of construction:
1. Draw a line segment AB of 11 cm.
2. Draw ∠DAB = 30° and ∠FBA = 90°.
3. Draw the angle bisectors of ∠DAB and ∠EBA which intersect each other at X.
4. Draw the perpendicular bisector of XA and XB which intersect AB at Y and Z respectively
5. Join XY and XZ.
Hence △XYZ is the required triangle.
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