Cu^2+ salt reacts with potassium
Question:

$\mathrm{Cu}^{2+}$ salt reacts with potassium iodide to give

  1. $\mathrm{Cu}_{2} \mathrm{I}_{2}$

  2. $\mathrm{Cu}_{2} \mathrm{I}_{3}$

  3. Cul

  4. $\mathrm{Cu}\left(\mathrm{I}_{3}\right)_{2}$


Correct Option: 1

Solution:

$2 \mathrm{Cu}^{+2}+4 \mathrm{I}^{-} \longrightarrow \mathrm{Cu}_{2} \mathrm{I}_{2}(\mathrm{~s})+\mathrm{I}_{2}$

$2 \mathrm{Cu}^{+2}+3 \mathrm{I}^{-} \longrightarrow 2 \mathrm{CuI}+\mathrm{I}_{2}$

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