Cube of
Question:

Cube of $\frac{-1}{2}$ is

(a) $\frac{1}{8}$

(b) $\frac{1}{16}$

(c) $-\frac{1}{8}$

(d) $\frac{-1}{16}$

Solution:

(c) -1/8

The cube of a number is the number raised to the power of 3. Hence the cube of −1/2 is

$\frac{(-1)^{3}}{2^{3}} \quad \cdots\left((a / b)^{n}=\left(a^{n}\right) /\left(b^{n}\right)\right.$

$-\frac{1}{8}$