Question.
Curved surface area of a right circular cylinder is $4.4 \mathrm{~m}^{2}$. If the radius of the base of the cylinder is $0.7 \mathrm{~m}$, find its height. $\left[\right.$ Assume $\left.\pi=\frac{22}{7}\right]$
Solution:
Let the height of the circular cylinder be h.
Radius $(r)$ of the base of cylinder $=0.7 \mathrm{~m}$
CSA of cylinder $=4.4 \mathrm{~m}^{2}$
$2 \pi r h=4.4 \mathrm{~m}^{2}$
$\left(2 \times \frac{22}{7} \times 0.7 \times h\right) \mathrm{m}=4.4 \mathrm{~m}^{2}$
$h=1 \mathrm{~m}$
Therefore, the height of the cylinder is $1 \mathrm{~m}$.
Let the height of the circular cylinder be h.
Radius $(r)$ of the base of cylinder $=0.7 \mathrm{~m}$
CSA of cylinder $=4.4 \mathrm{~m}^{2}$
$2 \pi r h=4.4 \mathrm{~m}^{2}$
$\left(2 \times \frac{22}{7} \times 0.7 \times h\right) \mathrm{m}=4.4 \mathrm{~m}^{2}$
$h=1 \mathrm{~m}$
Therefore, the height of the cylinder is $1 \mathrm{~m}$.
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.