Determine graphically the vertices of the triangle, the equations of whose sides are given below :

Solution:

(i) Draw the 3 lines as given by equations

By taking x=1 = 1 cm on x−axis

And y =1=1cm on y−axis

$\frac{y}{4}-\frac{x}{8}=1$

$\frac{y}{2.8}-\frac{x}{14}=1$

$\frac{y}{1}-\frac{x}{0.5}=1$

Clearly from graph points of intersection three lines are

(−4,2) , (1,3), (2,5) 

(ii) Draw the 3 lines as given by equations 

By taking x=1 = 1 cm on x−axis

 

And y =1=1cm on y−axis

$y=0$

$y=x$

$\frac{y}{10 / 3}+\frac{x}{10 / 3}=1$