Divide 184 into two parts such that one-third of

Question:

Divide 184 into two parts such that one-third of one part may exceed one-seventh of another part by 8.

Solution:

Let the first part of 184 be $\mathrm{x}$.

Therefore, the other part will be $(184-\mathrm{x})$.

According to the question,

$\frac{1}{3} \mathrm{x}-\frac{1}{7}(184-\mathrm{x})=8$

or $\frac{7 \mathrm{x}-552+3 \mathrm{x}}{21}=8$

or $10 \mathrm{x}-552=168[$ After c ross multiplication $]$

or $10 \mathrm{x}=168+552$

or $\mathrm{x}=\frac{720}{10}=72$

Thus, the parts of 184 are 72 and $112(184-72=112)$.

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