Draw a square whose each side measures 4.8 cm.
Question:

Draw a square whose each side measures 4.8 cm.

Solution:

(i) Draw side $\mathrm{AB}=4.8 \mathrm{~cm}$.

(ii) From A, make an angle of $90^{\circ}$ and cut it at $4.8 \mathrm{~cm}$ and mark it point D.

(iii) From B, make an angle of $90^{\circ}$ and cut it at $4.8 \mathrm{~cm}$ and mark it point C.

(iv) Join C and D.

Thus, $\mathrm{ABCD}$ is the required square.

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