Draw the graph of equation 2x + 3y = 12.

Solution:

We are given, 2x + 3y = 12

We get,

$y=\frac{12-2 x}{3}$

Substituting, x = 0 in

$y=\frac{12-2 x}{3}$

We get,

$y=\frac{12-2 \times 0}{3}$

y = 12 – 2 × 63 

y = 0

Thus, we have the following table exhibiting the abscissa and ordinates of points on the line represented by the given equation

By plotting the given equation on the graph, we get the point B(0, 4) and C (6,0).

(i) Co-ordinates of the point whose y axis is 3 are A (3/2, 3)

(ii) Co-ordinates of the point whose x -coordinate is -3 are D (- 3, 6)