Draw the graph of equation 2x + 3y = 12.
Question:

Draw the graph of equation 2x + 3y = 12.

From the graph, find the co-ordinates of the point:

(i) whose y-coordinate is 3         

(ii) whose x coordinate is -3 

Solution:

We are given, 2x + 3y = 12

We get,

$y=\frac{12-2 x}{3}$

Substituting, x = 0 in

$y=\frac{12-2 x}{3}$

We get,

$y=\frac{12-2 \times 0}{3}$

y = 12 – 2 × 63 

y = 0

Thus, we have the following table exhibiting the abscissa and ordinates of points on the line represented by the given equation

By plotting the given equation on the graph, we get the point B(0, 4) and C (6,0).

(i) Co-ordinates of the point whose y axis is 3 are A (3/2, 3)

(ii) Co-ordinates of the point whose x -coordinate is -3 are D (- 3, 6) 

 

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