During a sale, colour pencils were being sold in packs of 24 each and crayons in packs of 32 each.

We are given that during a sale, color pencils were being sold in packs of 24 each and crayons in packs of 32 each. If we want full packs of both and the same number of pencils and crayons, we need to find the number of each we need to buy.

Given that

Number of color pencils in one pack = 24

Number of crayons in pack = 32.

Therefore, the least number of both colors to be purchased

L.C.M of 24 and $32=2 \times 2 \times 2 \times 2 \times 2 \times 3$

= 96

Hence, number of packs of pencils to bought

$\frac{96}{24}=4$

And number of packs of crayon to be bought

$\frac{96}{32}=3$