Eleven bags of wheat flour, each marked 5 kg,
Question.

Eleven bags of wheat flour, each marked 5 kg, actually contained the following weights of flour (in kg):

4.97 5.05 5.08 5.03 5.00 5.06 5.08 4.98 5.04 5.07 5.00

Find the probability that any of these bags chosen at random contains more than 5 kg of flour.

Solution:

Number of total bags = 11

Number of bags containing more than 5 kg of flour = 7

Hence, required probability, $P=\frac{7}{11}$
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