Question:
Factorise
$27 a^{3}+64 b^{3}$
Solution:
We know that
$x^{3}+y^{3}=(x+y)\left(x^{2}+y^{2}-x y\right)$
Given: $27 a^{3}+64 b^{3}$
$x=3 a, y=4 b$
$27 a^{3}+64 b^{3}=(3 a+4 b)\left(9 a^{2}+16 b^{2}-12 a b\right)$
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