Factorize:
Question:

Factorize:

$(2 x-3)^{2}-8 x+12$

 

Solution:

We have:

$(2 x-3)^{2}-8 x+12=(2 x-3)^{2}-4(2 x-3)$

$=(2 x-3)[(2 x-3)-4]$

$=(2 x-3)(2 x-3-4)$

$=(2 x-3)(2 x-7)$

 

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