Question:
Factorize:
$a^{3}+a b(1-2 a)-2 b^{2}$
Solution:
We have:
$a^{3}+a b(1-2 a)-2 b^{2}=a^{3}+a b-2 a^{2} b-2 b^{2}$
$=\left(a^{3}-2 a^{2} b\right)+\left(a b-2 b^{2}\right)$
$=a^{2}(a-2 b)+b(a-2 b)$
$=(a-2 b)\left(a^{2}+b\right)$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.