Question:
Factorize:
$(3 a-1)^{2}-6 a+2$
Solution:
We have:
$(3 a-1)^{2}-6 a+2=(3 a-1)^{2}-2(3 a-1)$
$=(3 a-1)[(3 a-1)-2]$
$=(3 a-1)(3 a-1-2)$
$=(3 a-1)(3 a-3)$
$=3(3 a-1)(a-1)$
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