Find the 23rd term of the AP 7, 3, 1, –1, –3,

Question:

Find the $23^{\text {rd }}$ term of the AP $7,3,1,-1,-3, \ldots$

 

Solution:

To Find: $23^{\text {rd }}$ term of the AP

Given: The series is $7,5,3,1,-1,-3, \ldots$

$a_{1}=7, a_{2}=5$ and $d=3-5=-2$

(Where $a=a_{1}$ is first term, $a_{2}$ is second term, $a_{n}$ is nth term and $d$ is common difference of given $A P$ )

Formula Used: $a_{n}=a+(n-1) d$

So put n =23 in above formula, we have

$a_{23}=a_{1}+(23-1)(-2)=7-44=-37$

So $23^{\text {rd }}$ term of AP is equal to $-37$.

 

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