Find the centroid of ∆ABC whose vertices are A(−1, 0), B(5, −2) and C(8, 2).
Question:

Find the centroid of ∆ABC whose vertices are A(−1, 0), B(5, −2) and C(8, 2).

Solution:

Here, (x1 = −1, y1 = 0), (x2 = 5, y2 = −2) and (x3 = 8, y3 = 2).
Let G(xy) be the centroid of the ∆ABCThen,

$x=\frac{1}{3}\left(x_{1}+x_{2}+x_{3}\right)=\frac{1}{3}(-1+5+8)=\frac{1}{3}(12)=4$

$y=\frac{1}{3}\left(y_{1}+y_{2}+y_{3}\right)=\frac{1}{3}(0-2+2)=\frac{1}{3}(0)=0$

Hence, the centroid of ∆ABC is G(4, 0).

Administrator

Leave a comment

Please enter comment.
Please enter your name.