Find the coordinates of the focus, axis of the parabola,

The given equation is $x^{2}=-9 y$.

Here, the coefficient of y is negative. Hence, the parabola opens downwards.

On comparing this equation with $x^{2}=-4 a y$, we obtain

$-4 a=-9 \Rightarrow b=\frac{9}{4}$

$\therefore$ Coordinates of the focus $=(0,-a)=\left(0,-\frac{9}{4}\right)$

Since the given equation involves $x^{2}$, the axis of the parabola is the $y$-axis.

Equation of directrix, $y=a$, i.e., $y=\frac{9}{4}$

Length of latus rectum $=4 a=9$