Find the measure of an angle which is 36° more than its complement.
Question:

Find the measure of an angle which is 36° more than its complement.

 

Solution:

Let the measure of the required angle be $x^{\circ}$

Then, measure of its complement $=(90-x)^{\circ}$.

Therefore,

$x-\left(90^{\circ}-x\right)=36^{\circ}$

$\Rightarrow 2 x=126^{\circ}$

$\Rightarrow x=63^{\circ}$

Hence, the measure of the required angle is $63^{\circ}$.

 

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